Optimal. Leaf size=346 \[ -\frac{b^{5/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 a^{2/3} (b c-a d)^2}+\frac{b^{5/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} (b c-a d)^2}-\frac{b^{5/3} \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right )}{\sqrt{3} a^{2/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \log \left (c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2\right )}{18 c^{5/3} (b c-a d)^2}-\frac{d^{2/3} (5 b c-2 a d) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )}{9 c^{5/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \tan ^{-1}\left (\frac{\sqrt [3]{c}-2 \sqrt [3]{d} x}{\sqrt{3} \sqrt [3]{c}}\right )}{3 \sqrt{3} c^{5/3} (b c-a d)^2}-\frac{d x}{3 c \left (c+d x^3\right ) (b c-a d)} \]
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Rubi [A] time = 0.270003, antiderivative size = 346, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 8, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.421, Rules used = {414, 522, 200, 31, 634, 617, 204, 628} \[ -\frac{b^{5/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 a^{2/3} (b c-a d)^2}+\frac{b^{5/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} (b c-a d)^2}-\frac{b^{5/3} \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right )}{\sqrt{3} a^{2/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \log \left (c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2\right )}{18 c^{5/3} (b c-a d)^2}-\frac{d^{2/3} (5 b c-2 a d) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )}{9 c^{5/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \tan ^{-1}\left (\frac{\sqrt [3]{c}-2 \sqrt [3]{d} x}{\sqrt{3} \sqrt [3]{c}}\right )}{3 \sqrt{3} c^{5/3} (b c-a d)^2}-\frac{d x}{3 c \left (c+d x^3\right ) (b c-a d)} \]
Antiderivative was successfully verified.
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Rule 414
Rule 522
Rule 200
Rule 31
Rule 634
Rule 617
Rule 204
Rule 628
Rubi steps
\begin{align*} \int \frac{1}{\left (a+b x^3\right ) \left (c+d x^3\right )^2} \, dx &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}+\frac{\int \frac{3 b c-2 a d-2 b d x^3}{\left (a+b x^3\right ) \left (c+d x^3\right )} \, dx}{3 c (b c-a d)}\\ &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}+\frac{b^2 \int \frac{1}{a+b x^3} \, dx}{(b c-a d)^2}-\frac{(d (5 b c-2 a d)) \int \frac{1}{c+d x^3} \, dx}{3 c (b c-a d)^2}\\ &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}+\frac{b^2 \int \frac{1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx}{3 a^{2/3} (b c-a d)^2}+\frac{b^2 \int \frac{2 \sqrt [3]{a}-\sqrt [3]{b} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{3 a^{2/3} (b c-a d)^2}-\frac{(d (5 b c-2 a d)) \int \frac{1}{\sqrt [3]{c}+\sqrt [3]{d} x} \, dx}{9 c^{5/3} (b c-a d)^2}-\frac{(d (5 b c-2 a d)) \int \frac{2 \sqrt [3]{c}-\sqrt [3]{d} x}{c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2} \, dx}{9 c^{5/3} (b c-a d)^2}\\ &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}+\frac{b^{5/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} (b c-a d)^2}-\frac{d^{2/3} (5 b c-2 a d) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )}{9 c^{5/3} (b c-a d)^2}-\frac{b^{5/3} \int \frac{-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{6 a^{2/3} (b c-a d)^2}+\frac{b^2 \int \frac{1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{2 \sqrt [3]{a} (b c-a d)^2}+\frac{\left (d^{2/3} (5 b c-2 a d)\right ) \int \frac{-\sqrt [3]{c} \sqrt [3]{d}+2 d^{2/3} x}{c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2} \, dx}{18 c^{5/3} (b c-a d)^2}-\frac{(d (5 b c-2 a d)) \int \frac{1}{c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2} \, dx}{6 c^{4/3} (b c-a d)^2}\\ &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}+\frac{b^{5/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} (b c-a d)^2}-\frac{d^{2/3} (5 b c-2 a d) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )}{9 c^{5/3} (b c-a d)^2}-\frac{b^{5/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 a^{2/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \log \left (c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2\right )}{18 c^{5/3} (b c-a d)^2}+\frac{b^{5/3} \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )}{a^{2/3} (b c-a d)^2}-\frac{\left (d^{2/3} (5 b c-2 a d)\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1-\frac{2 \sqrt [3]{d} x}{\sqrt [3]{c}}\right )}{3 c^{5/3} (b c-a d)^2}\\ &=-\frac{d x}{3 c (b c-a d) \left (c+d x^3\right )}-\frac{b^{5/3} \tan ^{-1}\left (\frac{\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt{3} \sqrt [3]{a}}\right )}{\sqrt{3} a^{2/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \tan ^{-1}\left (\frac{\sqrt [3]{c}-2 \sqrt [3]{d} x}{\sqrt{3} \sqrt [3]{c}}\right )}{3 \sqrt{3} c^{5/3} (b c-a d)^2}+\frac{b^{5/3} \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 a^{2/3} (b c-a d)^2}-\frac{d^{2/3} (5 b c-2 a d) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )}{9 c^{5/3} (b c-a d)^2}-\frac{b^{5/3} \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 a^{2/3} (b c-a d)^2}+\frac{d^{2/3} (5 b c-2 a d) \log \left (c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2\right )}{18 c^{5/3} (b c-a d)^2}\\ \end{align*}
Mathematica [A] time = 0.204087, size = 336, normalized size = 0.97 \[ \frac{-3 b^{5/3} c^{5/3} \left (c+d x^3\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )+a^{2/3} d^{2/3} \left (c+d x^3\right ) (5 b c-2 a d) \log \left (c^{2/3}-\sqrt [3]{c} \sqrt [3]{d} x+d^{2/3} x^2\right )+6 a^{2/3} c^{2/3} d x (a d-b c)+2 a^{2/3} d^{2/3} \left (c+d x^3\right ) (2 a d-5 b c) \log \left (\sqrt [3]{c}+\sqrt [3]{d} x\right )-2 \sqrt{3} a^{2/3} d^{2/3} \left (c+d x^3\right ) (2 a d-5 b c) \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{d} x}{\sqrt [3]{c}}}{\sqrt{3}}\right )+6 b^{5/3} c^{5/3} \left (c+d x^3\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )-6 \sqrt{3} b^{5/3} c^{5/3} \left (c+d x^3\right ) \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt{3}}\right )}{18 a^{2/3} c^{5/3} \left (c+d x^3\right ) (b c-a d)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.012, size = 406, normalized size = 1.2 \begin{align*}{\frac{b}{3\, \left ( ad-bc \right ) ^{2}}\ln \left ( x+\sqrt [3]{{\frac{a}{b}}} \right ) \left ({\frac{a}{b}} \right ) ^{-{\frac{2}{3}}}}-{\frac{b}{6\, \left ( ad-bc \right ) ^{2}}\ln \left ({x}^{2}-\sqrt [3]{{\frac{a}{b}}}x+ \left ({\frac{a}{b}} \right ) ^{{\frac{2}{3}}} \right ) \left ({\frac{a}{b}} \right ) ^{-{\frac{2}{3}}}}+{\frac{b\sqrt{3}}{3\, \left ( ad-bc \right ) ^{2}}\arctan \left ({\frac{\sqrt{3}}{3} \left ( 2\,{x{\frac{1}{\sqrt [3]{{\frac{a}{b}}}}}}-1 \right ) } \right ) \left ({\frac{a}{b}} \right ) ^{-{\frac{2}{3}}}}+{\frac{{d}^{2}xa}{3\, \left ( ad-bc \right ) ^{2}c \left ( d{x}^{3}+c \right ) }}-{\frac{bdx}{3\, \left ( ad-bc \right ) ^{2} \left ( d{x}^{3}+c \right ) }}+{\frac{2\,ad}{9\, \left ( ad-bc \right ) ^{2}c}\ln \left ( x+\sqrt [3]{{\frac{c}{d}}} \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}}-{\frac{5\,b}{9\, \left ( ad-bc \right ) ^{2}}\ln \left ( x+\sqrt [3]{{\frac{c}{d}}} \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}}-{\frac{ad}{9\, \left ( ad-bc \right ) ^{2}c}\ln \left ({x}^{2}-\sqrt [3]{{\frac{c}{d}}}x+ \left ({\frac{c}{d}} \right ) ^{{\frac{2}{3}}} \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}}+{\frac{5\,b}{18\, \left ( ad-bc \right ) ^{2}}\ln \left ({x}^{2}-\sqrt [3]{{\frac{c}{d}}}x+ \left ({\frac{c}{d}} \right ) ^{{\frac{2}{3}}} \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}}+{\frac{2\,d\sqrt{3}a}{9\, \left ( ad-bc \right ) ^{2}c}\arctan \left ({\frac{\sqrt{3}}{3} \left ( 2\,{x{\frac{1}{\sqrt [3]{{\frac{c}{d}}}}}}-1 \right ) } \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}}-{\frac{5\,b\sqrt{3}}{9\, \left ( ad-bc \right ) ^{2}}\arctan \left ({\frac{\sqrt{3}}{3} \left ( 2\,{x{\frac{1}{\sqrt [3]{{\frac{c}{d}}}}}}-1 \right ) } \right ) \left ({\frac{c}{d}} \right ) ^{-{\frac{2}{3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 44.628, size = 994, normalized size = 2.87 \begin{align*} \frac{6 \, \sqrt{3}{\left (b c d x^{3} + b c^{2}\right )} \left (\frac{b^{2}}{a^{2}}\right )^{\frac{1}{3}} \arctan \left (\frac{2 \, \sqrt{3} a x \left (\frac{b^{2}}{a^{2}}\right )^{\frac{2}{3}} - \sqrt{3} b}{3 \, b}\right ) - 2 \, \sqrt{3}{\left ({\left (5 \, b c d - 2 \, a d^{2}\right )} x^{3} + 5 \, b c^{2} - 2 \, a c d\right )} \left (\frac{d^{2}}{c^{2}}\right )^{\frac{1}{3}} \arctan \left (\frac{2 \, \sqrt{3} c x \left (\frac{d^{2}}{c^{2}}\right )^{\frac{2}{3}} - \sqrt{3} d}{3 \, d}\right ) - 3 \,{\left (b c d x^{3} + b c^{2}\right )} \left (\frac{b^{2}}{a^{2}}\right )^{\frac{1}{3}} \log \left (b^{2} x^{2} - a b x \left (\frac{b^{2}}{a^{2}}\right )^{\frac{1}{3}} + a^{2} \left (\frac{b^{2}}{a^{2}}\right )^{\frac{2}{3}}\right ) +{\left ({\left (5 \, b c d - 2 \, a d^{2}\right )} x^{3} + 5 \, b c^{2} - 2 \, a c d\right )} \left (\frac{d^{2}}{c^{2}}\right )^{\frac{1}{3}} \log \left (d^{2} x^{2} - c d x \left (\frac{d^{2}}{c^{2}}\right )^{\frac{1}{3}} + c^{2} \left (\frac{d^{2}}{c^{2}}\right )^{\frac{2}{3}}\right ) + 6 \,{\left (b c d x^{3} + b c^{2}\right )} \left (\frac{b^{2}}{a^{2}}\right )^{\frac{1}{3}} \log \left (b x + a \left (\frac{b^{2}}{a^{2}}\right )^{\frac{1}{3}}\right ) - 2 \,{\left ({\left (5 \, b c d - 2 \, a d^{2}\right )} x^{3} + 5 \, b c^{2} - 2 \, a c d\right )} \left (\frac{d^{2}}{c^{2}}\right )^{\frac{1}{3}} \log \left (d x + c \left (\frac{d^{2}}{c^{2}}\right )^{\frac{1}{3}}\right ) - 6 \,{\left (b c d - a d^{2}\right )} x}{18 \,{\left (b^{2} c^{4} - 2 \, a b c^{3} d + a^{2} c^{2} d^{2} +{\left (b^{2} c^{3} d - 2 \, a b c^{2} d^{2} + a^{2} c d^{3}\right )} x^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.12082, size = 598, normalized size = 1.73 \begin{align*} -\frac{b^{2} \left (-\frac{a}{b}\right )^{\frac{1}{3}} \log \left ({\left | x - \left (-\frac{a}{b}\right )^{\frac{1}{3}} \right |}\right )}{3 \,{\left (a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2}\right )}} + \frac{\left (-a b^{2}\right )^{\frac{1}{3}} b \arctan \left (\frac{\sqrt{3}{\left (2 \, x + \left (-\frac{a}{b}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{a}{b}\right )^{\frac{1}{3}}}\right )}{\sqrt{3} a b^{2} c^{2} - 2 \, \sqrt{3} a^{2} b c d + \sqrt{3} a^{3} d^{2}} + \frac{\left (-a b^{2}\right )^{\frac{1}{3}} b \log \left (x^{2} + x \left (-\frac{a}{b}\right )^{\frac{1}{3}} + \left (-\frac{a}{b}\right )^{\frac{2}{3}}\right )}{6 \,{\left (a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2}\right )}} + \frac{{\left (5 \, b c d - 2 \, a d^{2}\right )} \left (-\frac{c}{d}\right )^{\frac{1}{3}} \log \left ({\left | x - \left (-\frac{c}{d}\right )^{\frac{1}{3}} \right |}\right )}{9 \,{\left (b^{2} c^{4} - 2 \, a b c^{3} d + a^{2} c^{2} d^{2}\right )}} - \frac{{\left (5 \, \left (-c d^{2}\right )^{\frac{1}{3}} b c - 2 \, \left (-c d^{2}\right )^{\frac{1}{3}} a d\right )} \arctan \left (\frac{\sqrt{3}{\left (2 \, x + \left (-\frac{c}{d}\right )^{\frac{1}{3}}\right )}}{3 \, \left (-\frac{c}{d}\right )^{\frac{1}{3}}}\right )}{3 \,{\left (\sqrt{3} b^{2} c^{4} - 2 \, \sqrt{3} a b c^{3} d + \sqrt{3} a^{2} c^{2} d^{2}\right )}} - \frac{{\left (5 \, \left (-c d^{2}\right )^{\frac{1}{3}} b c - 2 \, \left (-c d^{2}\right )^{\frac{1}{3}} a d\right )} \log \left (x^{2} + x \left (-\frac{c}{d}\right )^{\frac{1}{3}} + \left (-\frac{c}{d}\right )^{\frac{2}{3}}\right )}{18 \,{\left (b^{2} c^{4} - 2 \, a b c^{3} d + a^{2} c^{2} d^{2}\right )}} - \frac{d x}{3 \,{\left (d x^{3} + c\right )}{\left (b c^{2} - a c d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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